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Section summary |
---|
1. Efficiency of a
cyclone |
2. Calculation of
the efficiency of a cyclone : step by step calculation |
3. Example of
cyclone efficiency estimation |
4. Free Excel calculation tool for estimating a cyclone efficiency |
Cyclones are designed to separate the solids particles from a flow of gas. Cyclones are however not perfect and usually cannot capture all the dust present in a given gas. The capacity of a cyclone to catch the particles in a given gas is called the efficiency of the cyclone. This page present a shortcut calculation to estimate the efficiency of a cyclone.
The efficiency of a cyclone represents the proportion of particles that the cyclone can retain :
Efficiency = (inlet_loading -
outlet_loading)/inlet_loading*100
with :
Efficiency = the efficiency of the cyclone (%)
inlet_loading = the concentration of solids in the gas entering
the cyclone (kg/m3 or grains/ft3)
outlet_loading = the concentration of solids in the gas leaving
the cyclone (kg/m3 or grains / ft3)
You must gather data on : the cyclone to check, the gas flow, and the solids particles characteristics.
The cut diameter is the diameter of particles for which 50% of those particles are collected by the cyclone. Bigger particles will be collected at >50%, smaller particles will be collected at <50%
The cut diameter can be calculated with the following formula [Chopey] :
dpc = [9*μ*Bc/2*π*nt*vi*(ρp-ρ)]0.5
With :
dpc = cut diameter (microns)
μ = gas viscosity (lb/ft.s)
Bc = cyclone inlet width (ft)
nt = number of effective turns in the cyclone (-)
vi = inlet gas velocity (ft/s)
ρp = particle density (lb/ft3)
ρ = gas density (lb/ft3)
The ratio is equal to :
particle size ratio = dp/dpc
With :
dp = mean particle diameter of the particles in the
inlet flow (microns)
dpc = cut diameter (microns)
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In order to quickly estimate the cyclone efficiency from the calculations above, the Lapple's curve can be used. This abacus is shown below :
One must use the particle size ratio in order to estimate a cyclone efficiency.
It is also possible to use the following formula [Chopey] :
Efficiency = E = 1/(1+(dpc/dp)2)
With :
E = Efficiency of the cyclone (%)
dp = mean particle diameter of the particles in the
inlet flow (microns)
dpc = cut diameter (microns)
Once the efficiency of the cyclone is estimated, it is also possible to estimate the load of the gas flow out of the cyclone.
outlet_loading = inlet_loading*(1-E)
A factory needs to reduce the level of particles emissions out of a particular workshop. A second hand cyclone is available, having a diameter of 0.6 m, an inlet width of 0.15 m and is rated for 5 effective turns. The factory would like to know what will be the efficiency of the cyclone on the workshop air exhaust flow having a load of 17.65 grains / m3, with solids particles of 2500 kg/m3 and mean diameter of 10 microns. On the conditions considered, the inlet velocity of the air flow is 15 m/s and the air viscosity is 1.8*10-5 Pa.s and the air density is 1.2 kg/m3.
From the data above, one can identify :
μ = gas viscosity (Pa.s) = 1.8*10-5 Pa.s
Bc = cyclone inlet width (m) = 0.15 m
nt = number of effective turns in the cyclone (-) = 5
vi = inlet gas velocity (m/s) = 15 m/s
ρp = particle density (kg/m3) = 2500 kg/m3
ρ = gas density (kg/m3) = 1.2 kg/m3
dp = mean particle diameter of the particles in the inlet flow
(microns) = 10 microns
The following formula can be used to calculate the cut diameter :
dpc = [9*μ*Bc/2*π*nt*vi*(ρp-ρ)]0.5
However one must note that the inputs must be translated to imperial units.
μ = gas viscosity (Pa.s) = 1.8*10-5 Pa.s = 1.21*10-5 lb/ft.s
Bc = cyclone inlet width (m) = 0.15 m = 0.49 ft
nt = number of effective turns in the cyclone (-) = 5
vi = inlet gas velocity (m/s) = 15 m/s = 49.2 ft/s
ρp = particle density (kg/m3) = 2500 kg/m3 =
156 lb/ft3
ρ = gas density (kg/m3) = 1.2 kg/m3 = 0.075 lb/ft3
dp = mean particle diameter of the particles in the inlet flow
(microns) = 10 microns
dpc = [9*1.21*10-5*0.49/2*π*5*49.2*(156-0.075)]0.5 = 4.54 microns
The particle size ratio is simply dp/dpc = 2.2
The efficiency can be estimate with the following formula :
Efficiency = E = 1/(1+(dpc/dp)2) = 1/(1+(1/2.2)2) = 0.829
The efficiency is thus estimated for this application at 82.9%
It is always good to double check with Lapple's curve.
Thanks to the efficiency of 0.829, the loading of the air flow leaving the cyclone can be calculated as :
outlet_loading = inlet_loading*(1-E) = 17.65*(1-0.829) = 3.02 grains/m3
The cyclone operator can then compare this value to the regulation for example and determine if the cyclone is suitable.
The efficiency of a cyclone based on the calculations shown
above can be estimated thanks to this free Excel calculator : Calculation Tool - Cyclone efficiency
estimation (click here)
Warning : this calculator is provided to illustrate the concepts mentioned in this webpage, it is not intended for detail design. Please consult a reputable designer for all detail design you may need.
[Chopey] Handbook of Chemical Engineering Calculations, Chopey, MacGraw Hill